Lecture 17 - Tue 2023 11 07 Two times scales; van der Pol for small gain % =============================================================================== % % ----------------------------------------------------------------------------- % Two times scales example. We will consider the vdp equations for small gain: \ddot{x} + x + eps (x^2-1)\dot{x} = 0; [A] where 0 < \epsilon \ll 1. % % ----------------------------------------------------------------------------- % Bit of physics and Hopf bifurcation. But first a bit of physics: The equation represents the balance of several effects a) Inductance-Capacitance (oscillations). This alone would give \ddot{x} + x = 0; where a time scale such that the frequency is "one" has been selected [we use this time scale everywhere]. b) Resistance [Ohm's law]. This alone would give \ddot{x} + R \dot{x} = 0; where 1/R > 0 is the typical time of decay for the current in the circuit in units of the frequency. c) A (nonlinear) feed-back loop that pumps energy into the system. This alone would give \ddot{x} = A \dot{x} - B x^2 \dot{x}; where A and B are positive constants. Here we assume "small" amplitude and keep only the first nonlinear correction. There is no x \dot{x} term because the feedback does not depend on the sign of x. Adding it all yields: \ddot{x} + (R-A)\dot{x} + B x^2 \dot{x} + x = 0. Then we assume that A is slightly bigger than R, with \epsilon = A - R, and select a scale for x in which B = epsilon. WHY THIS SCALE? We will see next that this is the scale at which the oscillations arise, i.e.: for [A] the limit cycle has size O(1). NOTE THAT this last transformation can only be done when epsilon > 0; the nonlinear term always has the same sign. Thus the vdp equation only makes sense for epsilon > 0. It is easier to see the physics by writing the equation in the form [choose scale for x so that B = 1] \ddot{x} - \epsilon \dot{x} + x^2 \dot{x} + x = 0. [B] Then what happens is: for epsilon < 0, the circuit does not oscillate, and the solution remains at x \equiv 0. For epsilon > 0, a limit cycle of size sqrt{epsilon} appears, and we can reduce [B] to [A] by scaling x. THIS IS AN EXAMPLE OF A --------------> HOPF BIFURCATION % % ----------------------------------------------------------------------------- % The two times example. Do the example using the approach in the notes Hopf bifurcations using two timing and complex notation. I will add to these notes a typed version of the hand-written notes I used for the lecture. % % =============================================================================== EOF