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We may use Stokes' Theorem to deduce this by applying it to a tiny rectangle
normal to the w1 direction with sides obeying one of dw2 =
0 and dw3 = 0, and then cyclically permuting the indices.
The surface integral in Stokes' theorem then becomes
u2u3dw2dw3(v)1
while the path integrals become
which gives us: