Home | 18.022 | Chapter 2 | Section 2.2
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Suppose
a = ax i + ay j + az k
b = bx i + by j +bz k
Then
ab = (aybz - azby) i + (azbx - axbz) j + (axby - aybx) k
(1,01) (1,0,1) = 0;
(1,1,1) (1,1,0) = (-1,1,0)
To check your answer: check that answer is orthogonal to each factor.