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Solve the differential equation y ' = cos x
initial condition:
y2 - 18 = sinx2 - sin0
y2 = sin x2 + 18
the solution is:
y = sin x + 18
another initial condition:
y2 - 2 =sin x2 - sin 1
y2 = sin x2 + 2 - sin 1
the solution is:
y = sin x + 2 -sin 1